Question

Ребята, не могу разобраться помогите пожалуйста! Расставить коэффициенты методом электронного баланса, Составить электронные уравнения. Ca+HNO3(разб)-> Ca(NO3)2+N2O+H2O Cl2+NaOH->NaCl+NaClO3+H2O

Answer 1

4Ca + 10HNO3 = 4Ca(NO3)2 + N2O + 5H2O

Ca(0) - 2e = Ca(+2)

N(+5) + 4e = N+

3Cl2 + 6NaOH = 5NaCl + NaClO3 + 3H2O

Cl2(0) + 2e = 2Cl(-)

Cl2(0) - 10e = 2Cl(+5)

Answer 2

Balancing Chemical Equations using the Electron Balance Method

To balance the given chemical equation using the electron balance method, we need to ensure that the number of atoms of each element is the same on both sides of the equation. We will start by balancing the atoms that appear in the fewest compounds first.

The given chemical equation is:

Ca + HNO3(разб) -> Ca(NO3)2 + N2O + H2O

Let's start by balancing the calcium (Ca) atoms:

On the left side, we have 1 Ca atom, and on the right side, we have 1 Ca atom in Ca(NO3)2. So, the calcium atoms are already balanced.

Next, let's balance the nitrogen (N) atoms:

On the left side, we have 1 N atom in HNO3, and on the right side, we have 2 N atoms in Ca(NO3)2 and 1 N atom in N2O. To balance the nitrogen atoms, we need to multiply HNO3 by 2:

Ca + 2HNO3(разб) -> Ca(NO3)2 + N2O + H2O

Now, let's balance the oxygen (O) atoms:

On the left side, we have 6 O atoms in 2HNO3, and on the right side, we have 6 O atoms in Ca(NO3)2 and 1 O atom in N2O. The oxygen atoms are already balanced.

Finally, let's balance the hydrogen (H) atoms:

On the left side, we have 6 H atoms in 2HNO3, and on the right side, we have 2 H atoms in H2O. To balance the hydrogen atoms, we need to multiply H2O by 3:

Ca + 2HNO3(разб) -> Ca(NO3)2 + N2O + 3H2O

Now, let's move on to the next chemical equation:

Cl2 + NaOH -> NaCl + NaClO3 + H2O

First, let's balance the chlorine (Cl) atoms:

On the left side, we have 2 Cl atoms in Cl2, and on the right side, we have 1 Cl atom in NaCl and 1 Cl atom in NaClO3. To balance the chlorine atoms, we need to multiply NaCl by 2:

Cl2 + 2NaOH -> 2NaCl + NaClO3 + H2O

Next, let's balance the sodium (Na) atoms:

On the left side, we have 2 Na atoms in 2NaOH, and on the right side, we have 2 Na atoms in 2NaCl and 1 Na atom in NaClO3. The sodium atoms are already balanced.

Finally, let's balance the oxygen (O) atoms:

On the left side, we have 2 O atoms in 2NaOH, and on the right side, we have 1 O atom in NaClO3 and 1 O atom in H2O. To balance the oxygen atoms, we need to multiply NaClO3 by 3:

Cl2 + 2NaOH -> 2NaCl + 3NaClO3 + H2O

Now, the chemical equations are balanced using the electron balance method:

Ca + 2HNO3(разб) -> Ca(NO3)2 + N2O + 3H2O

Cl2 + 2NaOH -> 2NaCl + 3NaClO3 + H2O

Please note that the coefficients in front of the chemical formulas represent the number of molecules or moles of each substance involved in the reaction.