Question

K2SO4 + BaCl2 =KCl + HNO3 =HBr + Na2SO4 =​

Answer 1

ответ: K2SO4+BaCl2=2ksl+Baso4

KCl+HNO3=KNO3+HCl

HBr+Na2SO4=H2So4+Nabr(-1)

Answer 2

The chemical equation you've provided appears to be a series of reactions involving different compounds. Let's break down each step of the reaction:

1. K2SO4 + BaCl2 This reaction involves the double displacement or precipitation reaction. It will produce two new compounds: BaSO4 (barium sulfate) and KCl (potassium chloride).

   The balanced equation for this step is: K2SO4 + BaCl2 → BaSO4 + 2KCl

2. KCl + HNO3 In this step, potassium chloride (KCl) reacts with nitric acid (HNO3) to form potassium nitrate (KNO3) and hydrochloric acid (HCl).

   The balanced equation for this step is: KCl + HNO3 → KNO3 + HCl

3. HBr + Na2SO4 In this step, hydrobromic acid (HBr) reacts with sodium sulfate (Na2SO4) to form sodium bromide (NaBr) and sulfuric acid (H2SO4).

   The balanced equation for this step is: HBr + Na2SO4 → NaBr + H2SO4

If you want to represent the entire series of reactions as a single equation, you can combine the individual equations:

K2SO4 + BaCl2 → BaSO4 + 2KCl KCl + HNO3 → KNO3 + HCl HBr + Na2SO4 → NaBr + H2SO4

The overall reaction can be written as follows:

K2SO4 + BaCl2 + KCl + HNO3 + HBr + Na2SO4 → BaSO4 + 2KCl + KNO3 + HCl + NaBr + H2SO4