Question

Дано n(cl2)=0.4 найти:M-? m-? V-? N-? решение

Answer 1

N(постоянная Авогадро)= 6,02*10^23 или в некоторых источниках 6*10:23
M(Cl2)=70(35*2)
m(Cl2)= 0.4*70=28
V(Cl)= 0.4*22.4=8.96

Answer 2

Для решения необходимо использовать формулы:
 M=m:n, отсюда: m=Mxn 
Vm=V:n, отсюда: V=Vmxn  Vm=22,4л/моль
n=N:Na,  отсюда: N=nxNa   Na=6,02·10²³молекул

1. M(CI₂)=35,5х2=71г./моль

2. m(СI₂)=M(CI₂)хn(CI₂)=71г./мольх0,4моль=28,4г.

3.Vm=22,4л/моль
V(CI₂)=Vmхn(CI₂)=22,4л./мольх0,4моль=8,96л.

4. Na=6,02·10²³молекул
N(CI₂)=n(CI₂)хNa=0,4мольх6,02·10²³молекул=2,4·10²³молекул.

Answer 3

Task:

Find the values of M, m, V, and N when n(Cl2) = 0.4.

Solution:

The given information is n(Cl2) = 0.4. We need to find the values of M, m, V, and N.

Finding M:

To find M, we can use the given value of n(Cl2) and the molar mass of Cl2. The molar mass of Cl2 is 35.453 g/mol. Therefore, the molar mass of Cl2 (M(Cl2)) is 35.453 g/mol.

M(Cl2) = 35.453 g/mol.

Finding m:

The value of m is not explicitly defined in the given context. If you have a specific definition for m in this context, please provide it for further assistance.

Finding V:

The volume of a substance can be calculated using the ideal gas law, which states that V = nRT/P, where n is the number of moles, R is the ideal gas constant, T is the temperature in Kelvin, and P is the pressure.

However, the given information does not include the temperature or pressure, so it's not possible to calculate the volume (V) without this additional information.

Finding N:

The value of N is not explicitly defined in the given context. If you have a specific definition for N in this context, please provide it for further assistance.

Summary:

- M(Cl2) = 35.453 g/mol - The values of m and N are not explicitly defined in the given context. - The volume (V) cannot be calculated without additional information such as temperature and pressure.

If you have further details or specific definitions for m and N, or if you can provide additional information such as temperature and pressure, I'd be happy to assist further.