Question

M CH3COOH= 120 грам n CH3COOH -?

Answer 1

Объяснение:

вот ваша задание удачи в выполнении работ задание легкое главное учить

Answer 2

To find the number of moles (n) of acetic acid (CH3COOH) in 120 grams, you can use the formula:

n = mass (g) / molar mass (g/mol)

The molar mass of acetic acid (CH3COOH) can be calculated by adding up the molar masses of its constituent atoms:

Molar mass of C (carbon) = 12.01 g/mol Molar mass of H (hydrogen) = 1.01 g/mol Molar mass of O (oxygen) = 16.00 g/mol

Now, let's calculate the molar mass of acetic acid:

Molar mass of CH3COOH = (2 * Molar mass of C) + (4 * Molar mass of H) + (2 * Molar mass of O) Molar mass of CH3COOH = (2 * 12.01 g/mol) + (4 * 1.01 g/mol) + (2 * 16.00 g/mol) Molar mass of CH3COOH = 24.02 g/mol + 4.04 g/mol + 32.00 g/mol Molar mass of CH3COOH = 60.06 g/mol

Now, you can calculate the number of moles (n) using the given mass (120 grams) and the molar mass:

n = 120 g / 60.06 g/mol ≈ 1.998 moles

So, there are approximately 1.998 moles of acetic acid (CH3COOH) in 120 grams.