Question

C2h2-- (С акт)--> х1--(cl2,fe)-->x2--(koh, hoh)-->x3--(co2,hoh)-->x4--(br2,hoh)-->x4

Answer 1

3С2Н2-->С6Н6 (кат. Сакт, 600°С)
С6Н6+Cl2-->C6H5Cl (кат. FeCl3)
C6H5Cl+KOH(H2O)-->C6H5OH+KCl
C6H5OH+KOH-->C6H5OK+H2O (тут же реагирует с остатком щелочи)
C6H5OК+CO2+H2O-->C6H5OH+KHCO3
C6H5OH+3Br2-->C6H2Br3OH+3HBr (белый осадок 2,4,6-трибромфенола)

Answer 2

It looks like you've provided a sequence of chemical reactions. Let's break down each step:

1. C2H2 (acetylene) reacts with Cl2 in the presence of Fe (iron) catalyst.
2. The product from step 1, x1, reacts with Cl2 and Fe.
3. The product from step 2, x2, reacts with KOH (potassium hydroxide) and H2O (water).
4. The product from step 3, x3, reacts with CO2 and H2O.
5. The product from step 4, x4, reacts with Br2 and H2O.
6. The final product x4 is obtained.

It seems like you've outlined a series of reactions, but you haven't provided the specific reactants or products for each step. If you can provide more information about the reactants and products, I can help you with a more detailed explanation of the reactions.