Question

H2so3+lioh решение уравнения

Answer 1

H2so3+2lioh=2H2O+Li2SO3

Answer 2

$H_2SO_3 + 2LiOH \rightarrow Li_2SO_3 + 2H_2O$

Answer 3

To solve the chemical equation between H2SO3 (sulfurous acid) and LiOH (lithium hydroxide), we first need to balance the equation. The chemical equation is as follows:

H2SO3 + LiOH → ?

Let's balance the equation step-by-step:

1. Balance the hydrogen (H) atoms: On the left side, we have 2 hydrogen atoms from H2SO3, and on the right side, we have 1 hydrogen atom from LiOH. To balance it, we can place a coefficient of 2 in front of LiOH:

H2SO3 + 2LiOH → ?

Now the hydrogen atoms are balanced.

2. Balance the oxygen (O) atoms: On the left side, we have 3 oxygen atoms from H2SO3, and on the right side, we have 1 oxygen atom from LiOH. To balance it, we need to add a water molecule (H2O) to the right side, as it contains one oxygen atom:

H2SO3 + 2LiOH → H2O + ?

3. Balance the lithium (Li) atoms: On the left side, we have 2 lithium atoms from 2LiOH, and on the right side, we have 2 lithium atoms from LiOH. The lithium atoms are already balanced.

The balanced equation is now:

H2SO3 + 2LiOH → H2O + Li2SO3

Now, the chemical equation between H2SO3 (sulfurous acid) and LiOH (lithium hydroxide) is balanced, and the products are water (H2O) and lithium sulfite (Li2SO3).