Question

C3H8->C3H6->C3H2Br->C6H14->C6H6

Answer 1

Ответ смотри на фотографии.

Answer 2

The sequence of chemical reactions you've provided represents a series of transformations from the hydrocarbon propane (C3H8) to benzene (C6H6). Let's go through each step of the reaction sequence:

1. C3H8 (propane) -> C3H6 This is a dehydrogenation reaction where propane (C3H8) loses two hydrogen atoms to form propene (C3H6).

2. C3H6 (propene) -> C3H2Br This is a bromination reaction where propene (C3H6) reacts with bromine (Br2) to form 1,2-dibromo-1-propene (C3H2Br).

3. C3H2Br (1,2-dibromo-1-propene) -> C6H14 In this step, 1,2-dibromo-1-propene (C3H2Br) undergoes a reaction known as a "double-bond shift," which rearranges the molecule to form n-hexane (C6H14).

4. C6H14 (n-hexane) -> C6H6 Finally, n-hexane (C6H14) undergoes a dehydrogenation reaction, losing hydrogen atoms, to form benzene (C6H6).

So, the overall transformation is: C3H8 -> C3H6 -> C3H2Br -> C6H14 -> C6H6

This sequence represents a set of chemical reactions, and each step involves specific reagents and conditions to proceed. If you need more detailed information on any specific step or the reaction conditions, feel free to ask!