Question

C+cl2+cr2o3=crcl3+co

Answer 1

3C+3Cl2+Cr2O3=2CrCl3+3CO

Answer 2

The chemical equation you provided seems to be unbalanced. Let's balance it step by step.

C + Cl2 + Cr2O3 = CrCl3 + CO

Step 1: Balance the number of atoms of each element on both sides of the equation, except for oxygen and hydrogen.

Count the atoms on the left-hand side (LHS): C: 1 carbon atom Cl: 2 chlorine atoms Cr: 2 chromium atoms O: 3 oxygen atoms

Count the atoms on the right-hand side (RHS): Cr: 1 chromium atom Cl: 3 chlorine atoms C: 1 carbon atom O: 1 oxygen atom

Step 2: Balance the oxygen atoms by adding water (H2O) molecules where needed.

There are 3 oxygen atoms on the LHS and only 1 on the RHS. To balance oxygen, we need to add 2 water molecules to the RHS:

C + Cl2 + Cr2O3 = CrCl3 + CO + 2H2O

Now, the oxygen atoms are balanced:

O: 3 (LHS) = 3 (RHS)

Step 3: Balance the hydrogen atoms by adding hydrogen ions (H+) where needed.

There are no hydrogen atoms on the LHS, and now we have 4 hydrogen atoms from the two water molecules on the RHS. To balance hydrogen, we need to add 4 hydrogen ions to the LHS:

C + Cl2 + Cr2O3 + 4H+ = CrCl3 + CO + 2H2O

Step 4: Finally, balance the charge by adding electrons (e-) where needed.

On the LHS, we have a charge of 4+ from the hydrogen ions (H+). On the RHS, we have a charge of 3+ from CrCl3.

To balance the charge, we need to add 1 electron (e-) to the LHS:

C + Cl2 + Cr2O3 + 4H+ + e- = CrCl3 + CO + 2H2O

Now the equation is balanced with respect to both atoms and charge. The balanced equation is:

C + Cl2 + Cr2O3 + 4H+ + e- = CrCl3 + CO + 2H2O