Question

K2CO3 + HCI >KCI+CO2+H2O ионное уровнение

Answer 1

2K(+) + CO3(2-) + 2H(+) + 2Cl(-) = 2K(+) + 2Cl(-) + CO2 + H2O

2H(+) + CO3(2-) = CO2 + H2O

Answer 2

To write the ionic equation for the reaction between potassium carbonate (K2CO3) and hydrochloric acid (HCl), first, we need to know that both K2CO3 and HCl are strong electrolytes that ionize completely in water.

The balanced molecular equation for the reaction is:

K2CO3 (aq) + 2HCl (aq) → 2KCl (aq) + CO2 (g) + H2O (l)

Now, let's break down the reactants into their ionic forms:

K2CO3 (aq) → 2K+ (aq) + CO3^2- (aq) 2HCl (aq) → 2H+ (aq) + 2Cl- (aq)

Since both K+ and Cl- ions are spectator ions (ions that appear on both sides of the equation and do not participate in the actual reaction), we can eliminate them from the ionic equation. The remaining ionic equation is:

CO3^2- (aq) + 2H+ (aq) → CO2 (g) + H2O (l)

So, the ionic equation for the reaction is:

CO3^2- (aq) + 2H+ (aq) → CO2 (g) + H2O (l)