Question

M ( р - ра AgNO3 )= 340г w ( AgNO3 )=0,002 Найти: ( AgNO3 )-?

Answer 1

m(чистого AgNO3) = 0,0068

Answer 2

To find the molar mass of AgNO3 (silver nitrate) based on the given information, we can use the formula:

Molar mass (AgNO3) = Mass (AgNO3) / moles (AgNO3)

First, let's calculate the number of moles of AgNO3 (n) using the formula:

n = mass / molar mass

where mass = 340 grams (given) molar mass (M) = unknown

The molar mass of AgNO3 is unknown, so we'll use "x" to represent it:

n = 340g / x

Next, we can use the weight percentage (w) to relate the mass of AgNO3 to the mass of AgNO3 in the compound:

w = (mass of AgNO3 / mass of compound) * 100

Given w = 0.002 (0.002% = 0.002 / 100), we can express the mass of AgNO3 in the compound:

mass of AgNO3 = w * mass of compound mass of AgNO3 = 0.002 * 340g

Now we can substitute the expression for the mass of AgNO3 into the equation for the number of moles:

n = (0.002 * 340g) / x

Now, we can solve for x (the molar mass of AgNO3):

x = (0.002 * 340g) / n

We need to know the molar mass of AgNO3 to find its value. If you have the molar mass of AgNO3 or any other additional information, please provide it so that we can proceed with the calculation.