M(C4H8)=112г m(CO2)-? v(CO2)-? n(CO2)-?
Ответы на вопрос
112 г. Х г
С4Н8. +.6 О2. =. 4СО2. +. 4Н2О
n=1 моль. n=4 моль
М=56 г/моль. М=44 г/моль
m=56 г. m=176 г
112 г. С4Н8. -. Х г СО2
56 г. С4Н8. -. 176 г СО2
m(CO2)=112*176/56=352 г
n(CO2)=m/M=352/44=8 моль
V(CO2)=Vm*n=22,4*8=.179,2 л
To calculate the mass, volume, and amount of carbon dioxide (CO2) produced from the combustion of C4H8 (butene), we first need to know the balanced chemical equation for the combustion reaction. The balanced equation for the combustion of butene (C4H8) is as follows:
C4H8 + 6O2 → 4CO2 + 4H2O
From this equation, we can see that 1 mole of C4H8 reacts with 6 moles of O2 to produce 4 moles of CO2 and 4 moles of H2O.
Given that the molar mass of C4H8 (butene) is 112 g/mol, we can proceed with the calculations.
- Calculate the molar mass of CO2 (carbon dioxide): The molar mass of carbon dioxide (CO2) is the sum of the molar masses of one carbon atom (C) and two oxygen atoms (O).
Molar mass of C = 12.01 g/mol Molar mass of O = 16.00 g/mol
Molar mass of CO2 = (1 * Molar mass of C) + (2 * Molar mass of O) = 12.01 + (2 * 16.00) = 44.01 g/mol
- Calculate the mass of CO2 produced: Since the balanced equation shows that 1 mole of C4H8 produces 4 moles of CO2, we can set up a proportion to find the mass of CO2 produced.
(1 mole C4H8 / 4 moles CO2) = (112 g C4H8 / x g CO2)
x = (112 g C4H8) * (4 moles CO2 / 1 mole C4H8) = 448 g CO2
So, the mass of CO2 produced in the reaction is 448 grams.
- Calculate the volume of CO2 produced: To calculate the volume of CO2, we'll need additional information about the reaction conditions, specifically the temperature and pressure. Under standard conditions (0°C or 273.15 K and 1 atm pressure), one mole of any ideal gas occupies 22.71 L.
However, since the temperature and pressure are not provided, we cannot calculate the exact volume of CO2 produced without this information.
- Calculate the amount (number of moles) of CO2 produced: We can use the mass of CO2 and its molar mass to calculate the number of moles of CO2 produced.
Number of moles of CO2 = Mass of CO2 / Molar mass of CO2 Number of moles of CO2 = 448 g / 44.01 g/mol ≈ 10.18 moles
So, the amount (number of moles) of CO2 produced in the reaction is approximately 10.18 moles.
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