Question

2HCL+NaSO3=2NaCL+SO2+H2O m(HCL)=14г. найти V(SO2)

Answer 1

1. Na2SO3 + HCl → SO2 + NaCl + H2O

2. Zn + Na2SO3 + HCl → ZnCl2 + H2S + NaCl + H2O

3. Na2SO3 + KMnO4 + HCl → MnCl2 + Na2SO4 + KCl + H2O

4. Na2SO3 + K2Cr2O7 + HCl → CrCl3 + Na2SO4 + KCl + H2O

5. Na2SO3 + HCl → H2SO3 + NaCl

6. H2S + Na2SO3 + HCl → S + NaCl + H2O

7. Na2S + Na2SO3 + HCl → S + NaCl + H2O

8. Mg + Na2SO3 + HCl → MgCl2 + H2S + NaCl + H2O

9. Na2SO3 + SnCl2 + HCl → SnS2 + SnCl4 + NaCl + H2O

10. Na2SO3 + K2Cr2O7 + HCl → CrCl2 + Na2SO4 + KCl + H2O

Answer 2

To find the volume of sulfur dioxide (SO2) produced in the reaction, we first need to calculate the number of moles of HCl reacted, then use stoichiometry to determine the number of moles of SO2 produced, and finally, use the ideal gas law to find the volume of SO2.

Step 1: Calculate moles of HCl Given mass of HCl (m(HCl)) = 14 g Molar mass of HCl (Molar mass HCl) = 1 g/mol (hydrogen) + 35.5 g/mol (chlorine) = 36.5 g/mol

Number of moles of HCl (n(HCl)) = m(HCl) / Molar mass HCl n(HCl) = 14 g / 36.5 g/mol ≈ 0.3836 mol

Step 2: Use stoichiometry to find moles of SO2 From the balanced equation, we see that the molar ratio between HCl and SO2 is 2:1. This means that 2 moles of HCl produce 1 mole of SO2.

Number of moles of SO2 (n(SO2)) = 1/2 * n(HCl) n(SO2) = 1/2 * 0.3836 mol ≈ 0.1918 mol

Step 3: Use the ideal gas law to find the volume of SO2 The ideal gas law equation is: PV = nRT

Where: P = pressure of the gas (we'll assume standard pressure, which is 1 atm) V = volume of the gas (to be found) n = number of moles of the gas (0.1918 mol in our case) R = ideal gas constant (0.0821 L.atm/mol.K) T = temperature in Kelvin (we'll assume room temperature, which is 298 K)

V = nRT / P V = (0.1918 mol) * (0.0821 L.atm/mol.K) * (298 K) / 1 atm V ≈ 4.81 L

Therefore, the volume of sulfur dioxide (SO2) produced in the reaction is approximately 4.81 liters.