Question

BaCl2+H2SO4 эл диссоциацияMg(NO3)2+KON Эл диссоциация​

Answer 1

BaCl2 + H2SO4 = BaSO4 + 2HCl

Ba(2+) + 2Cl(-) + 2H(+) + SO4(2-) = BaSO4 + 2H(+) + 2Cl(-)

Ba(2+) + SO4(2-) = BaSO4

Mg(NO3)2 + 2KOH = Mg(OH)2 + 2KNO3

Mg(2+) + 2NO3(-) + 2K(+) + 2OH(-) = Mg(OH)2 + 2K(+) + 2NO3(-)

Mg(2+)+ 2OH(-)= Mg(OH)2

Answer 2

The chemical equations you provided represent the dissociation of two different compounds in water. Let's break down each one:

1. Dissociation of BaCl2 in water: BaCl2 (s) + H2O (l) ⟶ Ba^2+ (aq) + 2Cl^- (aq)

When solid barium chloride (BaCl2) is dissolved in water, it dissociates into barium ions (Ba^2+) and chloride ions (Cl^-).

2. Dissociation of Mg(NO3)2 in water: Mg(NO3)2 (s) + H2O (l) ⟶ Mg^2+ (aq) + 2NO3^- (aq)

When solid magnesium nitrate (Mg(NO3)2) is dissolved in water, it dissociates into magnesium ions (Mg^2+) and nitrate ions (NO3^-).

3. Dissociation of KNO3 in water: KNO3 (s) + H2O (l) ⟶ K^+ (aq) + NO3^- (aq)

When solid potassium nitrate (KNO3) is dissolved in water, it dissociates into potassium ions (K^+) and nitrate ions (NO3^-).

It's important to note that dissociation occurs when an ionic compound is dissolved in a solvent (such as water) and the individual ions separate from each other due to the solvent's polarity. The charges on the ions allow them to be surrounded by water molecules (hydration) and remain in solution as dissolved ions.