
M(K)=78г v(O2)=? K+O2=


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4K + O2 == 2K2O
n(K)= m:M = 78г:39г/моль = 2 моль |=> n(O2) = n(K) = 0.5 моль
n(O2)= V(O2):22.4 л/моль |=> V(O2)= 0.5 моль * 22.4 л/моль = 11.2 л



It seems like you've provided information about a chemical reaction involving potassium (K) and oxygen (O2) but you are missing some important details. The information you've given is "M(K) = 78g," which seems to indicate the molar mass of potassium, and "v(O2) = ?," which is unclear.
To balance a chemical equation, we need to know the reactants and products in the reaction. Since you've mentioned potassium (K) and oxygen (O2), I assume you want to know the product of the reaction when potassium reacts with oxygen.
The balanced chemical equation for the reaction between potassium and oxygen is:
4K + O2 → 2K2O
In this reaction, four atoms of potassium (4K) react with one molecule of oxygen gas (O2) to produce two molecules of potassium oxide (K2O).
If you meant something else or have additional information, please provide more context, and I'll be happy to assist further.


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