Question

2.2дихлорбутан + NaOH=

Answer 1

Ответ:Уравнение: CH2Cl-CH2-CH2-CH2Cl + 2NaOH--->

CH2OH-CH2-CH2-CH2OH + 2NaCl бутандиол-1,4

Answer 2

When 2,2-dichlorobutane reacts with NaOH (sodium hydroxide), it undergoes a nucleophilic substitution reaction known as an elimination reaction.

The balanced equation for this reaction is as follows:

2,2-dichlorobutane + NaOH -> 2-butene + NaCl + H2O

In this reaction, the NaOH acts as a base, abstracting a proton (H+) from the 2,2-dichlorobutane molecule. This leads to the formation of an alkoxide ion and the removal of a chloride ion. The alkoxide ion then undergoes elimination, resulting in the formation of the alkene 2-butene. Sodium chloride (NaCl) and water (H2O) are also formed as byproducts.

It's important to note that the reaction may require specific conditions such as heating or the presence of a catalyst to proceed efficiently.