Question

M(Fe)=28 m(FeS)=44 m(S)=?

Answer 1

Ответ: 72 потому что я умный человек

Answer 2

To find the molar mass of sulfur (m(S)), we need to use the given information about the molar masses of iron (m(Fe)) and iron(II) sulfide (m(FeS)).

The molar mass of iron (Fe) is given as 28 g/mol (grams per mole).

The molar mass of iron(II) sulfide (FeS) is given as 44 g/mol.

Iron(II) sulfide (FeS) consists of one iron atom (Fe) and one sulfur atom (S). Therefore, we can set up the equation:

m(Fe) + m(S) = m(FeS)

Substituting the given values:

28 g/mol + m(S) = 44 g/mol

Now, we can solve for m(S):

m(S) = 44 g/mol - 28 g/mol

m(S) = 16 g/mol

Therefore, the molar mass of sulfur (m(S)) is 16 g/mol.