Question

M(CaO)=112г найти m(Ca)(OM)2-?​

Answer 1

Ответ:

Объяснение:

112 г                                    Х г

CaO      +      H2O     =      Ca(OH)2

n=1 моль                          n=1 моль

М = 56 г/моль                 М = 74 г/моль

m=56 г                              m=74 г

112 г   СаО    -    Х г    Са(ОН)2

56 г    СаО   -   74 г    Са(ОН)2

m(Ca(OH)2) = 112 * 74 / 56 = 148 г

Answer 2

To find the mass of calcium in calcium oxide (CaO) given that the mass of CaO is 112 g, we need to determine the molar mass of CaO and then calculate the mass of calcium.

The molar mass of CaO can be obtained by summing the atomic masses of its constituent elements:

M(Ca) = 40.08 g/mol (molar mass of calcium) M(O) = 16.00 g/mol (molar mass of oxygen)

M(CaO) = M(Ca) + M(O) 112 g = 40.08 g/mol + 16.00 g/mol

Now, we can solve for the moles of CaO:

n(CaO) = mass/M(CaO) n(CaO) = 112 g / (40.08 g/mol + 16.00 g/mol) n(CaO) = 112 g / 56.08 g/mol n(CaO) ≈ 1.995 mol

Since the stoichiometry of calcium oxide (CaO) is 1:1 between calcium (Ca) and calcium oxide, the moles of calcium will also be approximately 1.995 mol.

Finally, we can calculate the mass of calcium (Ca) using its molar mass:

m(Ca) = n(Ca) * M(Ca) m(Ca) ≈ 1.995 mol * 40.08 g/mol m(Ca) ≈ 79.9 g

Therefore, the mass of calcium (Ca) in calcium oxide (CaO) is approximately 79.9 grams.