Question

CH4 → C2H2→CH3 – COH→CH3 – COOH →CH3 – COOC3H7

Answer 1

Ответ:

Объяснение:

2CH4 -> CH=-CH + 3H2 (t=1500)

CH=-CH + H2O -> CH3COH (t, Hg)

CH3COH + Ag2O -> CH3COOH + 2Ag

CH3COOH + C3H7OH -> CH3COOC3H7 + H2O

Answer 2

The series of chemical reactions you've provided can be described step by step as follows:

1. CH4 (Methane) → C2H2 (Ethyne/Acetylene) This reaction is a form of dehydrogenation, where methane loses four hydrogen atoms to form ethyne (also known as acetylene). The reaction can be represented as follows: CH4 → C2H2 + 2H2

2. C2H2 (Ethyne/Acetylene) → CH3 – COH (Acetaldehyde) In this step, ethyne reacts with water (H2O) to form acetaldehyde. The reaction is a form of hydration, where ethyne adds one molecule of water across its triple bond to produce acetaldehyde: C2H2 + H2O → CH3 – COH

3. CH3 – COH (Acetaldehyde) → CH3 – COOH (Acetic Acid) Acetaldehyde undergoes oxidation to form acetic acid. The reaction typically involves the addition of oxygen (O2) or another oxidizing agent: CH3 – COH + O2 → CH3 – COOH

4. CH3 – COOH (Acetic Acid) → CH3 – COOC3H7 (Ethyl Acetate) In this final step, acetic acid reacts with ethanol (C2H5OH) to form ethyl acetate and water in a reaction known as esterification: CH3 – COOH + C2H5OH → CH3 – COOC2H5 + H2O

So, the overall series of reactions can be summarized as:

CH4 → C2H2 → CH3 – COH → CH3 – COOH → CH3 – COOC3H7