Question

M(Fe)=2г найти:n(FeO2)

Answer 1

Ответ:

0,036 моль (Я нашел массу оксида железа FeO. Возможно, в условии ошибка т.к оксида FeO₂ не существует)

Объяснение:

Найдем кол-во вещества железа:

n(Fe) = m / M = 2 г / 56 = 0,036 моль

Составим уравнение реакции:

2Fe + O₂ = 2FeO

Коэффициенты перед железом и оксидом железа совпадают, значит n(FeO) = n(Fe) = 0,036 моль

Answer 2

To find the number of moles (n) of FeO2 (iron(II) oxide), we need to first understand the balanced chemical equation for the reaction:

4 Fe + O2 -> 2 FeO2

From the balanced equation, we can see that for every 4 moles of Fe (iron), we need 1 mole of O2 (oxygen) to produce 2 moles of FeO2. Now, we have the molar mass of Fe, which is 2 g/mol.

Step 1: Calculate the molar mass of FeO2. The molar mass of FeO2 can be calculated as follows: Molar mass of FeO2 = (Molar mass of Fe) + 2 * (Molar mass of O) Molar mass of FeO2 = 2 g/mol + 2 * 16 g/mol (Since oxygen has a molar mass of approximately 16 g/mol) Molar mass of FeO2 = 2 g/mol + 32 g/mol Molar mass of FeO2 = 34 g/mol

Step 2: Calculate the number of moles (n) of FeO2. We are given the mass of Fe, which is 2 g. To calculate the number of moles, we use the formula:

n = Mass / Molar mass

n(Fe) = 2 g / 2 g/mol n(Fe) = 1 mol

Since 4 moles of Fe react to produce 2 moles of FeO2, and we have 1 mole of Fe, we can calculate the number of moles of FeO2:

n(FeO2) = (1 mol Fe) * (2 mol FeO2 / 4 mol Fe) n(FeO2) = 0.5 mol

So, the number of moles of FeO2 is 0.5 moles.