Question

FeCl3+NaOH=FeSO4+NaOH=CuSO4+NaOH=Cu(OH)->​

Answer 1

Ответ:

сори если не так

CuSO4 + 2NaOH = Cu(OH)2 + Na2SO4

FeCl3 + NaOH = Fe(OH)Cl2 + NaCl

Объяснение:

Answer 2

Ответ:

Ну смари, значит

1)FeCl3+3NaOH= Fe(OH)3(Осадок)+3NaCl

P.s. Если NaOH неогр. то скажи, ибо там реакция пойдет до конца

2)FeSO4 + NaOH = Fe(OH)2(осадок) + Na2SO4

3)CuSO4 + 2NaOH =  Cu(OH)2 + Na2SO4

Как я понял в 4 разложение и там не CuOH такого не существует,  а CU(OH)2

4) Cu(OH)2 = CuO + H2O

Answer 3

The chemical reactions you have provided are not balanced, and there is an inconsistency in the reactants and products mentioned. Let's balance the equations and clarify the reactants and products.

1. FeCl3 + NaOH → Fe(OH)3 + NaCl This equation represents the reaction between iron(III) chloride (FeCl3) and sodium hydroxide (NaOH) to form iron(III) hydroxide (Fe(OH)3) and sodium chloride (NaCl).

2. FeSO4 + NaOH → Fe(OH)2 + Na2SO4 This equation represents the reaction between iron(II) sulfate (FeSO4) and sodium hydroxide (NaOH) to form iron(II) hydroxide (Fe(OH)2) and sodium sulfate (Na2SO4).

3. CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4 This equation represents the reaction between copper(II) sulfate (CuSO4) and sodium hydroxide (NaOH) to form copper(II) hydroxide (Cu(OH)2) and sodium sulfate (Na2SO4).

It's important to note that the reaction between FeCl3 and NaOH produces Fe(OH)3, not FeSO4. Additionally, the reaction between FeSO4 and NaOH produces Fe(OH)2, not FeSO4. Lastly, the reaction between CuSO4 and NaOH produces Cu(OH)2, not Cu(OH)-.