Question

Cr2 (so4)3+NaoH→пліз​

Answer 1

Ответ:

Cr2(SO4)3 + 6NaOH = 2Cr(OH)3 + 3Na2SO4

Cr2(SO4)3 + 12NaOH = 2Na3[Cr(OH)6]

Объяснение :

Answer 2

Ответ:

Cr2(SO4)3+NaOH-> Na2SO4+ 2Cr(OH)3

При уравнивании мы получаем коэффициенты:

Cr2(SO4)3+NaOH=> 3Na2SO4+2Cr(OH)3

Объяснение:

Answer 3

The chemical equation you provided is:

Cr2(SO4)3 + NaOH → ?

To balance the equation and determine the products, we need to consider the stoichiometry of the reaction. Let's balance the equation step by step:

1. Balance the chromium (Cr) atoms: There are two chromium atoms on the left side, so we need to have two chromium atoms on the right side as well.

Cr2(SO4)3 + NaOH → Cr2(SO4)3 + NaOH

2. Balance the sulfur (S) atoms: There are three sulfur atoms in the chromium sulfate (Cr2(SO4)3) on the left side. To balance this, we will need three sulfate ions (SO4^2-) on the right side.

Cr2(SO4)3 + NaOH → Cr2(SO4)3 + 3NaOH

3. Balance the hydrogen (H) atoms: There are six hydrogen atoms in the three NaOH molecules on the right side. To balance this, we need six hydrogen atoms on the left side. We can achieve this by adding three water (H2O) molecules on the left side.

Cr2(SO4)3 + 3NaOH → Cr2(SO4)3 + 3NaOH + 3H2O

4. Balance the sodium (Na) atoms: There are three sodium atoms in the three NaOH molecules on the right side. To balance this, we need three sodium atoms on the left side. We can achieve this by adding three Na2SO4 molecules on the left side.

Cr2(SO4)3 + 3NaOH → Cr2(SO4)3 + 3NaOH + 3H2O + 3Na2SO4

Now, the equation is balanced. The products of the reaction are chromium sulfate (Cr2(SO4)3), sodium hydroxide (NaOH), water (H2O), and sodium sulfate (Na2SO4).