Question

C4H10->C2H4->C2H6,->C2H5CL->C4H10->C4H9CL->C6H14->CO2

Answer 1

Попробуем..

1.С2H6+CL2-->C2H5CL+HCL .

2C2H5CL+2Na-->C4H10+2NaCL  .

3.C4H10+CL2-->C4H9CL+HCL  .

4.C4H9CL+NaOH-->C4H9OH+NaCL  .

5.2C4H9OH+13O2-->8CO2+10H2O .

Удачи!

Answer 2

The series of chemical reactions you've mentioned appears to involve the transformation of various hydrocarbons and chlorinated compounds. Let's break down each step in the sequence:

1. C4H10 (Butane) -> C2H4 (Ethylene)

   • In this step, butane (C4H10) undergoes a process called cracking, which typically involves high temperatures and/or a catalyst. It breaks down into ethylene (C2H4).

2. C2H4 (Ethylene) -> C2H6 (Ethane)

   • Ethylene (C2H4) is hydrogenated to form ethane (C2H6).

3. C2H6 (Ethane) -> C2H5Cl (Chloroethane)

   • Ethane (C2H6) can react with hydrogen chloride (HCl) to form chloroethane (C2H5Cl).

4. C2H5Cl (Chloroethane) -> C4H10 (Butane)

   • Chloroethane (C2H5Cl) can undergo a substitution reaction, where the chlorine atom is replaced by a hydrogen atom, resulting in the formation of butane (C4H10).

5. C4H10 (Butane) -> C4H9Cl (Chlorobutane)

   • Butane (C4H10) can also undergo a substitution reaction, similar to step 4, to form chlorobutane (C4H9Cl).

6. C4H9Cl (Chlorobutane) -> C6H14 (Hexane)

   • Chlorobutane (C4H9Cl) can react with a nucleophile (e.g., sodium iodide) to undergo a substitution reaction, forming hexane (C6H14).

7. C6H14 (Hexane) -> CO2 (Carbon Dioxide)

   • Hexane (C6H14) can undergo combustion, typically with oxygen, to produce carbon dioxide (CO2) and water (H2O) as products.

These reactions represent a series of chemical transformations involving the conversion of different hydrocarbons and chlorinated compounds. Each step involves specific chemical reactions and conditions.