Question

Mr(LiOH)= Mr(MgH2)= Mr(Al(NO3)3)=

Answer 1

Объяснение:

Mr(LiOH)=7+16+1=24

Mr(MgH2)=24+1*2=26

Mr(Al(NO3)3=27+14*3+16*9=213

Answer 2

To find the molar masses (Mr) of the given compounds:

1. Lithium Hydroxide (LiOH):

   • Li has a molar mass of approximately 6.94 g/mol.
   • O has a molar mass of approximately 16.00 g/mol.
   • H has a molar mass of approximately 1.01 g/mol.

   Mr(LiOH) = 6.94 (Li) + 16.00 (O) + 1.01 (H) = 23.95 g/mol

2. Magnesium Hydride (MgH2):

   • Mg has a molar mass of approximately 24.31 g/mol.
   • H has a molar mass of approximately 1.01 g/mol.

   Mr(MgH2) = 24.31 (Mg) + 1.01 (H) + 1.01 (H) = 26.33 g/mol

3. Aluminum Nitrate (Al(NO3)3):

   • Al has a molar mass of approximately 26.98 g/mol.
   • N has a molar mass of approximately 14.01 g/mol.
   • O has a molar mass of approximately 16.00 g/mol.

   Mr(Al(NO3)3) = 26.98 (Al) + 3(14.01 (N) + 3(16.00 (O))) = 26.98 + 42.03 + 144.00 = 213.01 g/mol

So, the molar masses are:

• Mr(LiOH) = 23.95 g/mol
• Mr(MgH2) = 26.33 g/mol
• Mr(Al(NO3)3) = 213.01 g/mol