Question

1)Li2O+H2So4=LiHSo4+H2O2)KOH+HCL=KCL+......​

Answer 1

1) Li2O + 2H2SO4 = 2LiHSO4 + H2O

2) KOH + HCl = KCl + H2O

как-то так

Answer 2

Let's balance the chemical equations you provided:

1. Li2O + H2SO4 → LiHSO4 + H2O

First, let's balance the elements in the equation:

• For lithium (Li), we have 2 on the left and 1 on the right. To balance it, put a coefficient of 2 in front of LiHSO4:

Li2O + H2SO4 → 2LiHSO4 + H2O

• For sulfur (S), we have 1 on the left and 2 on the right. To balance it, put a coefficient of 2 in front of H2SO4:

Li2O + 2H2SO4 → 2LiHSO4 + H2O

• For hydrogen (H), we have 4 on the left and 4 on the right. It's already balanced.

• For oxygen (O), we have 2 on the left and 9 on the right. To balance it, put a coefficient of 7/2 in front of H2O:

Li2O + 2H2SO4 → 2LiHSO4 + 7/2 H2O

To get rid of the fractional coefficient, multiply the entire equation by 2:

2Li2O + 4H2SO4 → 4LiHSO4 + 7H2O

So, the balanced equation is:

2Li2O + 4H2SO4 → 4LiHSO4 + 7H2O

2. KOH + HCl → KCl + H2O

This equation is already balanced. Each element has the same number of atoms on both sides:

• For potassium (K), we have 1 on both sides.
• For hydrogen (H), we have 1 on both sides.
• For chlorine (Cl), we have 1 on both sides.
• For oxygen (O), we have 1 on both sides.

So, the balanced equation is:

KOH + HCl → KCl + H2O