Question

H313 1104 ALV4a) Al → Al2(SO4)3 → AICI3 Al(OH)3 → Al(NO3)3 → Al2O3​

Answer 1

Ответ:

Відповідь на малюнку

Объяснение:

Answer 2

Ответ:

2Al + 3H2SO4 → Al2(SO4)3 + 3H2

Al2(SO4)3 + 3CaCl2 → 2AlCl3 + 3CaSO4

3NaOH + AlCl3 → Al(OH)3 + 3NaCl

Al(OH)3 + 3HNO3 → Al(NO3)3 + 3H2O

4Al(NO3)3 → 2Al2O3 + 12NO2 + 3O2

Answer 3

It seems like you've provided a chemical equation with various compounds involving aluminum (Al) and different reactions. The equation appears to show the transformation of aluminum (Al) through several reactions. Let me break down each step for you:

1. Al → Al2(SO4)3:

   • In this step, aluminum (Al) reacts with sulfuric acid (H2SO4) to form aluminum sulfate, Al2(SO4)3. This is a typical acid-base reaction.

2. Al2(SO4)3 → AlCl3:

   • Here, aluminum sulfate (Al2(SO4)3) reacts with hydrochloric acid (HCl) to form aluminum chloride (AlCl3). This is another acid-base reaction, and the sulfate ions (SO4^2-) are replaced by chloride ions (Cl^-).

3. AlCl3 → Al(OH)3:

   • In this step, aluminum chloride (AlCl3) reacts with water (H2O) to form aluminum hydroxide (Al(OH)3). This is a hydrolysis reaction.

4. Al(OH)3 → Al(NO3)3:

   • Aluminum hydroxide (Al(OH)3) reacts with nitric acid (HNO3) to form aluminum nitrate (Al(NO3)3). This is another acid-base reaction.

5. Al(NO3)3 → Al2O3:

   • Finally, aluminum nitrate (Al(NO3)3) undergoes thermal decomposition to produce aluminum oxide (Al2O3). This reaction involves the breaking of nitrate ions (NO3^-) and the formation of aluminum oxide.

Each of these reactions represents a chemical transformation of aluminum (Al) from one compound to another under specific reaction conditions. If you have any specific questions or need further information about any of these reactions, please feel free to ask.