Question

M(MgO) = 5г + CH3COOH​m(соли)=?

Answer 1

Ответ:

2MgO+4HNO3=2Mg(NO3)2+2H2O

5г ---------------- х г

80 ------------148

х=5*148/80=9.25г

Объяснение:

Answer 2

The chemical formula you've provided indicates that you have magnesium oxide (MgO) and acetic acid (CH3COOH). You've also mentioned "M(MgO) = 5g," which means you have 5 grams of magnesium oxide.

To find the molar mass of magnesium oxide (MgO), you need to add up the atomic masses of the constituent elements:

• Magnesium (Mg) has a molar mass of approximately 24.305 g/mol.
• Oxygen (O) has a molar mass of approximately 15.999 g/mol.

So, the molar mass of MgO is:

MgO = 24.305 g/mol (Mg) + 15.999 g/mol (O) ≈ 40.304 g/mol

Now that you have the molar mass of MgO, you can calculate the number of moles of MgO in 5 grams:

Number of moles = Mass (g) / Molar mass (g/mol) Number of moles of MgO = 5 g / 40.304 g/mol ≈ 0.124 moles

Next, you mentioned "m(соли)." If you are looking for the number of moles of the salt produced when magnesium oxide (MgO) reacts with acetic acid (CH3COOH), you'll need to write and balance the chemical equation for the reaction. The reaction between MgO and CH3COOH can produce magnesium acetate and water.

The balanced chemical equation is:

MgO + 2 CH3COOH → Mg(CH3COO)2 + H2O

From the balanced equation, you can see that one mole of MgO reacts with two moles of CH3COOH to produce one mole of magnesium acetate (Mg(CH3COO)2) and water (H2O). Since you have 0.124 moles of MgO, it will react with 0.124 moles of CH3COOH.

The molar mass of acetic acid (CH3COOH) is the sum of the molar masses of its constituent elements:

• Carbon (C) has a molar mass of approximately 12.011 g/mol.
• Hydrogen (H) has a molar mass of approximately 1.008 g/mol.
• Oxygen (O) has a molar mass of approximately 15.999 g/mol.

Molar mass of CH3COOH = 2(12.011 g/mol) + 4(1.008 g/mol) + 2(15.999 g/mol) ≈ 60.052 g/mol

Now, you can calculate the number of moles of CH3COOH:

Number of moles of CH3COOH = 0.124 moles of MgO × (1 mole of CH3COOH / 1 mole of MgO) = 0.124 moles

So, m(соли) = 0.124 moles of the salt produced when 0.124 moles of MgO react with 0.124 moles of CH3COOH according to the balanced chemical equation.