Question

Pb(OH)2 →рьо- Pb(NO3); → PbS;​

Answer 1

1. Pb(OH2) -> PbO + H2O (разложение)
2. PbO + 2HNO3 = Pb(NO3)2 + H2O
3. Pb(NO3)2 + H2S = PbS + 2HNO3

Answer 2

The chemical equation you provided is not balanced, and it appears to be incomplete. To properly balance and complete it, you should provide more information about the reaction conditions and the products involved. However, I can provide some information on how to balance chemical equations.

Here's a balanced chemical equation for the reaction of lead(II) hydroxide (Pb(OH)2) with lead(II) nitrate (Pb(NO3)2) to form lead(II) sulfide (PbS):

2Pb(OH)2 + 2Pb(NO3)2 → 4PbS + 4H2O + 4NO3^-

In this balanced equation:

• 2 moles of Pb(OH)2 react with 2 moles of Pb(NO3)2.
• This produces 4 moles of PbS (lead sulfide), 4 moles of water (H2O), and 4 moles of nitrate ions (NO3^-).

Please note that the reaction you provided appears to be incomplete, as chemical reactions usually involve specific conditions (e.g., temperature, pressure) and additional information to determine the full reaction. If you have additional information about the reaction or if you meant a different reaction, please provide more details for a more accurate explanation.