Question

Na2S+H2so4 = m(H2so4) =11,76г v(h2s)=?

Answer 1

Ответ:

V(H2S)=2.688 л

Объяснение:

Дано:

m(H2SO4)=11.76 г

Найти:

V(H2S)-?

Решение:

Na2S+H2SO4=Na2SO4+H2S(газ)

n(H2SO4)=m/M=11.76/98=0.12 моль;

n(H2S)=n(H2SO4)=0.12 моль;

V(H2S)=n*Vm=0.12*22.4=2.688 л

Answer 2

Ответ:

Объяснение:

Na2S + 4H2SO4(kонц) = Na2SO4 + 4H2O + 4SO2↑

Na2S + H2SO4(разб) = Na2SO4 + H2S↑

Na2S + H2SO4(pазб) = Na2SO4 + H2S↑

n(H2SO4)=m(H2SO4/M(H2SO4)=11.76/98=0.12mol

n(H2SO4)=n(H2S)

V(H2S)=n(H2S)*Vm=0.12*22.4=2.69л

Answer 3

To determine the volume of hydrogen sulfide gas (H2S) produced when sodium sulfide (Na2S) reacts with sulfuric acid (H2SO4), you need to follow these steps:

1. Balance the chemical equation for the reaction: Na2S + H2SO4 → 2NaHS + H2SO4

2. Calculate the molar mass of Na2S and H2S:

   • Molar mass of Na2S (sodium sulfide) = 2(22.99 g/mol) + 32.07 g/mol = 77.05 g/mol
   • Molar mass of H2S (hydrogen sulfide) = 2(1.01 g/mol) + 32.07 g/mol = 34.09 g/mol

3. Calculate the moles of H2SO4: Given mass of H2SO4 (m(H2SO4)) = 11.76 g Molar mass of H2SO4 = 2(1.01 g/mol) + 32.07 g/mol + 4(16.00 g/mol) = 98.09 g/mol

   Moles of H2SO4 = m(H2SO4) / Molar mass of H2SO4 Moles of H2SO4 = 11.76 g / 98.09 g/mol ≈ 0.12 moles

4. Using the balanced equation, you can see that 1 mole of Na2S produces 1 mole of H2S: Moles of H2S = Moles of H2SO4 ≈ 0.12 moles

5. Calculate the volume of H2S gas using the ideal gas law, assuming standard temperature and pressure (STP), where 1 mole of gas occupies 22.4 liters at STP:

   V(H2S) = Moles of H2S × 22.4 L/mol V(H2S) = 0.12 moles × 22.4 L/mol ≈ 2.69 liters

So, the volume of hydrogen sulfide gas (H2S) produced in this reaction is approximately 2.69 liters at standard temperature and pressure.