Question

ПОМОГИТЕ РЕШИТЬ!! Какова масса молекул гидроксида лития в 4 г гидроксида натрия?Жду пошаговых объяснении!!​

Answer 1

Ответ:

4гр - - - - - - - х=0.1моль

40 - - - - - - 1моль

1 мольLi2O - - - - - - - - 30 гр

0.1 моль - - - - - - - - - - - 3 гр

40 это масса гидроксида Натрия

30 это масса гидроксида лития

Answer 2

Calculation of the Molar Mass of Lithium Hydroxide

To determine the mass of lithium hydroxide (LiOH) in 4 g of sodium hydroxide (NaOH), we need to calculate the molar mass of lithium hydroxide and then use stoichiometry to find the mass.

The molar mass of lithium hydroxide can be calculated by summing the atomic masses of its constituent elements: lithium (Li), oxygen (O), and hydrogen (H).

The atomic masses of the elements are as follows: - Lithium (Li): 6.94 g/mol - Oxygen (O): 16.00 g/mol - Hydrogen (H): 1.01 g/mol

To calculate the molar mass of lithium hydroxide (LiOH), we add the atomic masses of each element: Molar mass of LiOH = (1 * atomic mass of Li) + (1 * atomic mass of O) + (1 * atomic mass of H)

Molar mass of LiOH = (1 * 6.94 g/mol) + (1 * 16.00 g/mol) + (1 * 1.01 g/mol) Molar mass of LiOH = 6.94 g/mol + 16.00 g/mol + 1.01 g/mol Molar mass of LiOH = 23.95 g/mol

Therefore, the molar mass of lithium hydroxide (LiOH) is 23.95 g/mol.

Calculation of the Mass of Lithium Hydroxide in 4 g of Sodium Hydroxide

To calculate the mass of lithium hydroxide (LiOH) in 4 g of sodium hydroxide (NaOH), we need to use the stoichiometry of the balanced chemical equation between sodium hydroxide and lithium hydroxide.

The balanced chemical equation for the reaction between sodium hydroxide and lithium hydroxide is: 2 NaOH + Li2CO3 → 2 LiOH + Na2CO3

From the balanced equation, we can see that 2 moles of sodium hydroxide (NaOH) react to form 2 moles of lithium hydroxide (LiOH).

To calculate the mass of lithium hydroxide (LiOH) in 4 g of sodium hydroxide (NaOH), we can use the following steps:

1. Calculate the molar mass of sodium hydroxide (NaOH). 2. Convert the mass of sodium hydroxide (NaOH) to moles. 3. Use the stoichiometry of the balanced equation to determine the moles of lithium hydroxide (LiOH). 4. Convert the moles of lithium hydroxide (LiOH) to mass.

Let's go through these steps:

1. The molar mass of sodium hydroxide (NaOH) can be calculated by summing the atomic masses of its constituent elements: sodium (Na), oxygen (O), and hydrogen (H).

Molar mass of NaOH = (1 * atomic mass of Na) + (1 * atomic mass of O) + (1 * atomic mass of H)

Molar mass of NaOH = (1 * 22.99 g/mol) + (1 * 16.00 g/mol) + (1 * 1.01 g/mol) Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol Molar mass of NaOH = 40.00 g/mol

Therefore, the molar mass of sodium hydroxide (NaOH) is 40.00 g/mol.

2. To convert the mass of sodium hydroxide (NaOH) to moles, we can use the formula:

Moles of NaOH = Mass of NaOH / Molar mass of NaOH

Moles of NaOH = 4 g / 40.00 g/mol Moles of NaOH = 0.1 mol

Therefore, there are 0.1 moles of sodium hydroxide (NaOH) in 4 g.

3. Since the stoichiometry of the balanced equation tells us that 2 moles of sodium hydroxide (NaOH) react to form 2 moles of lithium hydroxide (LiOH), we can determine the moles of lithium hydroxide (LiOH) using the following formula:

Moles of LiOH = (Moles of NaOH / 2) * 2

Moles of LiOH = (0.1 mol / 2) * 2 Moles of LiOH = 0.1 mol

Therefore, there are 0.1 moles of lithium hydroxide (LiOH) in 4 g of sodium hydroxide (NaOH).

4. Finally, to convert the moles of lithium hydroxide (LiOH) to mass, we can use the formula:

Mass of LiOH = Moles of LiOH * Molar mass of LiOH

Mass of LiOH = 0.1 mol * 23.95 g/mol Mass of LiOH = 2.395 g

Therefore, the mass of lithium hydroxide (LiOH) in 4 g of sodium hydroxide (NaOH) is 2.395 g.

Summary: The mass of lithium hydroxide (LiOH) in 4 g of sodium hydroxide (NaOH) is approximately 2.395 g.