Question

Напишите, пожалуйста, только дано. Магний массой 4,8 г растворили в 200 мл 12-%-ного раствора серной кислоты ( p = 1, 05 г/мл ). Вычислите массовую долю сульфата магния в конечном растворе.​

Answer 1

Ответ:

Mg=4,8г

р=1,05г/мл

вроде все

Answer 2

Calculation of the Mass Fraction of Magnesium Sulfate in the Final Solution

To calculate the mass fraction of magnesium sulfate in the final solution, we need to consider the mass of magnesium and the mass of sulfuric acid in the initial solution.

Given: - Mass of magnesium (Mg) = 4.8 g - Volume of 12% sulfuric acid solution = 200 mL - Density of 12% sulfuric acid solution (p) = 1.05 g/mL

To find the mass of sulfuric acid, we can use the formula:

Mass = Volume x Density

The mass of sulfuric acid in the initial solution is:

Mass of sulfuric acid = Volume of sulfuric acid x Density of sulfuric acid

Substituting the given values:

Mass of sulfuric acid = 200 mL x 1.05 g/mL

Now, we can calculate the mass fraction of magnesium sulfate in the final solution.

Calculation:

1. Calculate the molar mass of magnesium sulfate (MgSO4): - Molar mass of Mg = 24.31 g/mol - Molar mass of S = 32.07 g/mol - Molar mass of O = 16.00 g/mol (4 oxygen atoms in MgSO4) - Molar mass of MgSO4 = (24.31 g/mol) + (32.07 g/mol) + (16.00 g/mol x 4) = 120.37 g/mol

2. Calculate the moles of magnesium (Mg) in the initial solution: - Moles of Mg = Mass of Mg / Molar mass of Mg

3. Calculate the moles of sulfuric acid (H2SO4) in the initial solution: - Moles of H2SO4 = Mass of sulfuric acid / Molar mass of H2SO4

4. Calculate the moles of magnesium sulfate (MgSO4) formed in the reaction: - The balanced chemical equation for the reaction between magnesium and sulfuric acid is: Mg + H2SO4 → MgSO4 + H2 - From the equation, we can see that 1 mole of magnesium reacts with 1 mole of sulfuric acid to form 1 mole of magnesium sulfate.

Therefore, the moles of MgSO4 formed = Moles of Mg = Moles of H2SO4

5. Calculate the mass of magnesium sulfate (MgSO4) formed: - Mass of MgSO4 = Moles of MgSO4 x Molar mass of MgSO4

6. Calculate the mass fraction of magnesium sulfate (MgSO4) in the final solution: - Mass fraction of MgSO4 = Mass of MgSO4 / (Mass of MgSO4 + Mass of sulfuric acid)

Now, let's calculate the mass fraction of magnesium sulfate in the final solution using the given values and the above calculations.

Solution:

1. Calculate the mass of sulfuric acid: - Mass of sulfuric acid = 200 mL x 1.05 g/mL = 210 g

2. Calculate the moles of magnesium (Mg): - Moles of Mg = 4.8 g / 24.31 g/mol = 0.1976 mol

3. Calculate the moles of sulfuric acid (H2SO4): - Moles of H2SO4 = 210 g / (2 g/mol + 32.07 g/mol + 4 x 16.00 g/mol) = 2.91 mol

4. Calculate the moles of magnesium sulfate (MgSO4) formed: - Moles of MgSO4 = Moles of Mg = Moles of H2SO4 = 0.1976 mol

5. Calculate the mass of magnesium sulfate (MgSO4) formed: - Mass of MgSO4 = Moles of MgSO4 x Molar mass of MgSO4 = 0.1976 mol x 120.37 g/mol = 23.68 g

6. Calculate the mass fraction of magnesium sulfate (MgSO4) in the final solution: - Mass fraction of MgSO4 = Mass of MgSO4 / (Mass of MgSO4 + Mass of sulfuric acid) = 23.68 g / (23.68 g + 210 g) = 0.101

Therefore, the mass fraction of magnesium sulfate (MgSO4) in the final solution is approximately 10.1%.

Please note that the above calculation assumes that the reaction between magnesium and sulfuric acid goes to completion and that there are no other reactions or losses during the process.