Question

60%-й раствор серной кислоты имеет плотность 1,503. Определите молярность такой кислоты.​

Answer 1

Ответ:

Ответ: C = 1,68 моль/л......

Answer 2

Ответ:

Объяснение:

Дано

w(H2SO4)=60 %=0.6 м.д.

p(раствора)=1.503 г/мл?

Найти

C-?

Решение:

V(раствора)=m(раствора)/p(раствора)

C=n(H2SO4)/V=m(H2SO4)/(V*M)=w(H2SO4)*m(раствора)*p(раствора)/m(раствора)*M=w(H2SO4)*p(раствора)/M=0.6*1.503/98=0.0092 моль/мл=9.2 моль/л

Answer 3

Calculation of Molarity of 60% Sulfuric Acid Solution

To determine the molarity of a sulfuric acid solution, we need to know the concentration of the acid in terms of moles per liter (Molarity). In this case, we are given that the solution is a 60% sulfuric acid solution with a density of 1.503 g/mL.

To calculate the molarity, we can follow these steps:

1. Determine the molar mass of sulfuric acid (H2SO4). 2. Calculate the number of moles of sulfuric acid present in 1 mL of the solution. 3. Convert the number of moles per mL to moles per liter (Molarity).

Step 1: Determine the molar mass of sulfuric acid (H2SO4)

The molar mass of sulfuric acid (H2SO4) can be calculated by summing the atomic masses of its constituent elements:

- Atomic mass of hydrogen (H) = 1.00784 g/mol - Atomic mass of sulfur (S) = 32.06 g/mol - Atomic mass of oxygen (O) = 15.999 g/mol

Molar mass of H2SO4 = (2 * Atomic mass of hydrogen) + Atomic mass of sulfur + (4 * Atomic mass of oxygen)

Molar mass of H2SO4 = (2 * 1.00784 g/mol) + 32.06 g/mol + (4 * 15.999 g/mol)

Molar mass of H2SO4 = 98.09 g/mol

Step 2: Calculate the number of moles of sulfuric acid present in 1 mL of the solution

To calculate the number of moles of sulfuric acid in 1 mL of the solution, we need to know the mass of the acid present in 1 mL. We can calculate this using the density of the solution.

Given: - Density of the solution = 1.503 g/mL

Mass of 1 mL of the solution = Density * Volume

Mass of 1 mL of the solution = 1.503 g/mL * 1 mL = 1.503 g

Now, we can calculate the number of moles of sulfuric acid in 1 mL of the solution using the molar mass of sulfuric acid:

Number of moles of sulfuric acid = Mass of sulfuric acid / Molar mass of sulfuric acid

Number of moles of sulfuric acid = 1.503 g / 98.09 g/mol

Step 3: Convert the number of moles per mL to moles per liter (Molarity)

To convert the number of moles per mL to moles per liter (Molarity), we need to multiply the number of moles by 1000 (since there are 1000 mL in a liter).

Molarity of sulfuric acid = Number of moles of sulfuric acid * 1000

Now, let's calculate the molarity of the 60% sulfuric acid solution using the given information.

Molarity of 60% sulfuric acid solution:

Molarity = (Number of moles of sulfuric acid / 98.09 g/mol) * 1000

Please note that the exact calculation of the molarity requires the precise mass of sulfuric acid in the solution, which is not provided in the given information. Therefore, we cannot provide an accurate value for the molarity of the sulfuric acid solution based on the given information.

If you have the exact mass of sulfuric acid in the solution, please provide it, and we can calculate the molarity for you.