Question

Вариант 1 Используя метод электронного баланса, расставьте коэффициенты в уравнении реакции, схема которой: KNO2 + KI + H2SO4 + I2 +NO+ K2SO4 + H2O P+ H2SO4 + H3PO4+SO2+H2O KI+KIO3+H2SO4 +12+K2SO4+H2O H2S + KCIO3 -> S + KCl + H2O NH3+CuO + N2+H2O + Cu Определите окислитель и восстановитель

Answer 1

H2S + 8 HNO3 → H2SO4 + 8 NO2 + 4 H2O  

S(-2)-8е→S(+6) 1 ВОСТАНОВИТЕЛЬ , ОКИСЛЕНИЕ

N(+5)+1e→N(+4) 8 ОКИСЛИТЕЛЬ , ВОССТАНОВЛЕНИЕ

Answer 2

Balancing the Equation:

To balance the given chemical equation using the method of an electronic balance, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's go step by step:

1. Start by balancing the elements that appear in only one compound on each side of the equation. In this case, we have: - Nitrogen (N): There are 2 nitrogen atoms on the left side (KNO2) and 1 nitrogen atom on the right side (NO). To balance nitrogen, we need to put a coefficient of 2 in front of NO: KNO2 + KI + H2SO4 + I2 → 2NO + K2SO4 + H2O + P + H2SO4 + H3PO4 + SO2 + H2O + KI + KIO3 + H2SO4 + 12K2SO4 + H2O + H2S → S + KCl + H2O + NH3 + CuO + N2 + H2O + Cu.

2. Next, balance the oxygen atoms by adding water (H2O) molecules as needed. We have: - Oxygen (O): There are 4 oxygen atoms on the left side and 4 oxygen atoms on the right side. The equation is already balanced in terms of oxygen.

3. Now, balance the hydrogen atoms by adding hydrogen ions (H+) or water (H2O) molecules. We have: - Hydrogen (H): There are 8 hydrogen atoms on the left side and 8 hydrogen atoms on the right side. The equation is already balanced in terms of hydrogen.

4. Finally, balance the remaining elements, such as potassium (K), iodine (I), sulfur (S), and phosphorus (P), by adjusting the coefficients in front of the respective compounds. We have: - Potassium (K): There are 2 potassium atoms on the left side and 13 potassium atoms on the right side. To balance potassium, we need to put a coefficient of 6.5 (or 13/2) in front of K2SO4: **KNO2 + KI + H2SO4 + I2 → 2NO + 6.5K2SO4 +