Question

2. Виконати завдання. Перетворіть схеми реакцій на хімічні рівняння: а) РЬ + O2 - РЬОб) Ag + S - Ag2Sв) H2 + F2 - HFг) Li + O2. — Li2Oг) Mg + HCI – MgCl2 + H21д) Al(OH)3 - Al2O3 + H2OЯ не поняла цієі теми. Допоможіть, будь ласка Срочно!!!!!!!!

Answer 1

Объяснение:

а)  2 Pb + O2 → 2 PbO

б) 2 Ag + S → Ag2S

в) H2 + F2 → 2 HF

г) 4 Li + O2 → 2 Li2O

г) Mg + 2 HCl → H2 + MgCl2

д) 2 Al(OH)3  → Al2O3  + 3 H2O

Answer 2

Conversion of Reaction Schemes to Chemical Equations

a) Rb + O2 -> RbO2 - This reaction represents the combination of rubidium (Rb) with oxygen (O2) to form rubidium peroxide (RbO2) [[1]].

b) 2Ag+ + S -> Ag2S - This equation represents the reaction between silver ions (Ag+) and sulfur (S) to form silver sulfide (Ag2S) [[2]].

c) H2 + F2 -> 2HF - This equation represents the reaction between hydrogen (H2) and fluorine (F2) to form hydrogen fluoride (HF) [[3]].

d) 2Li + O2 -> 2Li2O - This equation represents the reaction between lithium (Li) and oxygen (O2) to form lithium oxide (Li2O) [[4]].

e) Mg + 2HCl -> MgCl2 + H2 - This equation represents the reaction between magnesium (Mg) and hydrochloric acid (HCl) to form magnesium chloride (MgCl2) and hydrogen gas (H2) [[5]].

f) 2Al(OH)3 -> Al2O3 + 3H2O - This equation represents the decomposition of aluminum hydroxide (Al(OH)3) into aluminum oxide (Al2O3) and water (H2O) [[6]].

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