Вопрос задан 18.06.2023 в 11:50. Предмет Химия. Спрашивает Сидякина Настя.

Найдите количество вещества ,объём (н.у.) и число молекул,содиржащихся в оксиде азота NO2 массой

4,6 кг.​
0 0
Перейти к ответам

Ответы на вопрос

Внимание! Ответы на вопросы дают живые люди. Они могут содержать ошибочную информацию, заблуждения, а также ответы могут быть сгенерированы нейросетями. Будьте внимательны. Если вы уверены, что ответ неверный, нажмите кнопку "Пожаловаться" под ответом.
Отвечает Лєщук Вікторія.

Ответ:

N(no2)=4.6/46=0.1

N=0.1*6*10^23=0.6*10^23

v=0.1*22.4=2.24

0 0
Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of the Amount of Substance, Volume (STP), and Number of Molecules in Nitrogen Dioxide (NO2)

To find the amount of substance, volume (STP), and number of molecules in nitrogen dioxide (NO2) with a mass of 4.6 kg, we can use the following steps:

1. Determine the molar mass of nitrogen dioxide (NO2). 2. Calculate the amount of substance (moles) using the given mass and molar mass. 3. Use Avogadro's number to find the number of molecules. 4. Calculate the volume at standard temperature and pressure (STP) using the ideal gas law.

Let's go through these steps in detail:

Step 1: Determine the Molar Mass of Nitrogen Dioxide (NO2)

The molar mass of nitrogen dioxide (NO2) can be calculated by adding up the atomic masses of nitrogen (N) and two oxygen (O) atoms.

The atomic mass of nitrogen (N) is approximately 14.01 g/mol, and the atomic mass of oxygen (O) is approximately 16.00 g/mol.

Therefore, the molar mass of nitrogen dioxide (NO2) is: Molar mass of NO2 = (atomic mass of N) + 2 * (atomic mass of O) Molar mass of NO2 = 14.01 g/mol + 2 * 16.00 g/mol Molar mass of NO2 = 46.01 g/mol.

Step 2: Calculate the Amount of Substance (moles)

The amount of substance (moles) can be calculated using the formula:

Amount of substance (moles) = Mass / Molar mass

Given that the mass of nitrogen dioxide (NO2) is 4.6 kg (or 4600 g), we can calculate the amount of substance as follows:

Amount of substance (moles) = 4600 g / 46.01 g/mol Amount of substance (moles) ≈ 100 moles.

Therefore, the amount of substance of nitrogen dioxide (NO2) is approximately 100 moles.

Step 3: Calculate the Number of Molecules

To find the number of molecules, we can use Avogadro's number, which is approximately 6.022 x 10^23 molecules per mole.

Number of molecules = Amount of substance (moles) * Avogadro's number Number of molecules ≈ 100 moles * (6.022 x 10^23 molecules/mole) Number of molecules ≈ 6.022 x 10^25 molecules.

Therefore, the number of molecules in nitrogen dioxide (NO2) with a mass of 4.6 kg is approximately 6.022 x 10^25 molecules.

Step 4: Calculate the Volume at Standard Temperature and Pressure (STP)

To calculate the volume at standard temperature and pressure (STP), we can use the ideal gas law, which states:

PV = nRT

Where: P = Pressure (STP is typically 1 atm) V = Volume n = Amount of substance (moles) R = Ideal gas constant (0.0821 L·atm/(mol·K)) T = Temperature (STP is typically 273.15 K)

Rearranging the equation to solve for V, we get:

V = (nRT) / P

Substituting the values, we have:

V = (100 moles * 0.0821 L·atm/(mol·K) * 273.15 K) / 1 atm V ≈ 2241.65 L.

Therefore, the volume of nitrogen dioxide (NO2) with a mass of 4.6 kg at standard temperature and pressure (STP) is approximately 2241.65 liters.

In summary: - The amount of substance (moles) in nitrogen dioxide (NO2) with a mass of 4.6 kg is approximately 100 moles. - The number of molecules in nitrogen dioxide (NO2) with a mass of 4.6 kg is approximately 6.022 x 10^25 molecules. - The volume of nitrogen dioxide (NO2) with a mass of 4.6 kg at standard temperature and pressure (STP) is approximately 2241.65 liters.

Please note that the above calculations are approximate and may vary slightly depending on the exact values used for atomic masses and Avogadro's number.

I hope this helps! Let me know if you have any further questions.

0 0

Похожие вопросы

Топ вопросов за вчера в категории Химия

Последние заданные вопросы в категории Химия

Задать вопрос