Question

9. Визначте ступені окиснення елементів у сполуках і проставте їх над їхнiми символами: ZnCl₂, K₂O, H₂S, CH4, H3PO4, H₂CO3, Ba(OH)₂. ​

Answer 1

Ответ:

Объяснение:

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Answer 2

Stupeni okysnennya elements in compounds:

1. ZnCl₂ (Zinc chloride): - Zinc (Zn) has a +2 oxidation state in this compound [[1]].

2. K₂O (Potassium oxide): - Potassium (K) has a +1 oxidation state in this compound [[2]].

3. H₂S (Hydrogen sulfide): - Hydrogen (H) has a +1 oxidation state in this compound [[3]]. - Sulfur (S) has a -2 oxidation state in this compound [[3]].

4. CH₄ (Methane): - Carbon (C) has a -4 oxidation state in this compound [[4]]. - Hydrogen (H) has a +1 oxidation state in this compound [[4]].

5. H₃PO₄ (Phosphoric acid): - Hydrogen (H) has a +1 oxidation state in this compound [[5]]. - Phosphorus (P) has a +5 oxidation state in this compound [[5]]. - Oxygen (O) has a -2 oxidation state in this compound [[5]].

6. H₂CO₃ (Carbonic acid): - Hydrogen (H) has a +1 oxidation state in this compound [[6]]. - Carbon (C) has a +4 oxidation state in this compound [[6]]. - Oxygen (O) has a -2 oxidation state in this compound [[6]].

7. Ba(OH)₂ (Barium hydroxide): - Barium (Ba) has a +2 oxidation state in this compound [[7]]. - Hydrogen (H) has a +1 oxidation state in this compound [[7]]. - Oxygen (O) has a -2 oxidation state in this compound [[7]].

Please note that the oxidation states mentioned above are based on the general rules and may vary in certain cases depending on the specific compound and its structure.

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