Question

7. Урівняйте схему реакціі методом електронного балансу, вкажіть окисники й відновники, а також процес окиснення та процес відновлення. Со + HNO3→ Co(NO3)2 + N2+ H2O​

Answer 1

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Answer 2

Balancing the Chemical Equation using the Electron Balance Method

To balance the chemical equation Co + HNO3 → Co(NO3)2 + N2 + H2O, we can use the electron balance method. This method involves balancing the number of electrons gained and lost during the reaction.

Let's break down the reaction into half-reactions for oxidation and reduction:

Oxidation Half-Reaction: Co → Co^2+ + 2e^-

Reduction Half-Reaction: HNO3 + 3e^- → NO3^- + 2H2O

Now, we need to balance the number of electrons in both half-reactions. To do this, we can multiply the oxidation half-reaction by 3 and the reduction half-reaction by 2:

Balanced Oxidation Half-Reaction: 3Co → 3Co^2+ + 6e^-

Balanced Reduction Half-Reaction: 2HNO3 + 6e^- → 2NO3^- + 4H2O

Next, we need to balance the number of atoms on both sides of the equation. We can do this by adjusting the coefficients:

Balanced Chemical Equation: 3Co + 2HNO3 → 3Co(NO3)2 + 2NO + 4H2O

Oxidizing Agent and Reducing Agent

In the balanced chemical equation, the oxidizing agent is the species that gets reduced, while the reducing agent is the species that gets oxidized.

In this reaction, Co is oxidized from its elemental state (Co) to Co^2+, so it is the reducing agent. HNO3 is reduced from +5 oxidation state to +2 in Co(NO3)2, so it is the oxidizing agent.

Oxidation Process and Reduction Process

The oxidation process involves the loss of electrons, while the reduction process involves the gain of electrons.

In this reaction, the oxidation process occurs when Co loses electrons and is oxidized to Co^2+. The reduction process occurs when HNO3 gains electrons and is reduced to NO3^-.

To summarize: - Oxidation process: Co → Co^2+ + 2e^- - Reduction process: HNO3 + 3e^- → NO3^- + 2H2O

Please let me know if you need any further clarification or have any other questions!