Question

Какой объем (н.у.) водорода (в л) содержит столько же электронов, что и 60 г магния. Ответ приведите с точностью до целых без указания размерности.

Answer 1

Ответ:

224 литра

Объяснение:

1 молекула магния содержит 12 электронов.

60 г магния содержит 60/24 × 6.02 × 10²³ = 15.05 × 10²³ молекул.

15.05 × 10²³ молекул содержит 15.05 × 10²³ × 12 = 180,6 × 10²³ электронов.

1 молекула водорода содержит 2 электрона.

180,6 × 10²³ электронов содержится в 180,6 × 10²³ / 2 = 60,3 × 10²³ молекулах водорода.

n (H2) = N / Na = 60,3 × 10²³ / 6.02 × 10²³ ≈ 10 моль

V (H2) = n × Vm = 10 × 22.4 = 224 литра

Answer 2

Calculation of Hydrogen Volume

To determine the volume of hydrogen gas (at standard temperature and pressure) that contains the same number of electrons as 60 grams of magnesium, we need to consider the molar mass and Avogadro's number.

1. Find the molar mass of magnesium (Mg): - The molar mass of magnesium is approximately 24.31 grams per mole.

2. Calculate the number of moles of magnesium: - Divide the given mass of magnesium (60 grams) by its molar mass: ``` Number of moles of magnesium = 60 g / 24.31 g/mol ≈ 2.47 mol ```

3. Use Avogadro's number to find the number of electrons in 2.47 moles of magnesium: - Avogadro's number is approximately 6.022 × 10^23 electrons per mole. - Multiply the number of moles of magnesium by Avogadro's number: ``` Number of electrons in 2.47 moles of magnesium = 2.47 mol × (6.022 × 10^23 electrons/mol) ≈ 1.49 × 10^24 electrons ```

4. Calculate the volume of hydrogen gas (at standard temperature and pressure) that contains the same number of electrons: - The molar mass of hydrogen is approximately 1.008 grams per mole. - Divide the number of electrons (1.49 × 10^24 electrons) by Avogadro's number to get the number of moles of hydrogen: ``` Number of moles of hydrogen = (1.49 × 10^24 electrons) / (6.022 × 10^23 electrons/mol) ≈ 2.47 mol ``` - Multiply the number of moles of hydrogen by its molar volume at standard temperature and pressure (22.4 liters/mol) to get the volume of hydrogen gas: ``` Volume of hydrogen gas = 2.47 mol × 22.4 L/mol ≈ 55.33 L ```

Therefore, the volume of hydrogen gas (at standard temperature and pressure) that contains the same number of electrons as 60 grams of magnesium is approximately 55 liters.

Please note that this calculation assumes ideal gas behavior and standard temperature and pressure conditions.