Question

масова частка Гідраргіуму в сполуці з Оксигеном дорівнює 96,2 відсотки.Відносна молекулярна маса цієї сполуки-416.Визначте формулу сполуки HgxOy​

Answer 1

Ответ:

Hg2O (оксид ртуті)

Объяснение:

W (O) = 100% - 96,2% = 3,8%

Знайдемо кількість атомів кожного елемента за формулою: n = W × Mr/Ar × 100

n (Hg) = 96,2% × 416/201 × 100 = 40019,2/20100 ≈2

n (O) = 3,8% × 416/16 × 100 = 1580,8/1600 ≈ 1

Отримаємо Hg 2 O 1

Answer 2

Chemical Compound Calculation

The mass percentage of mercury in the compound can be calculated using the given information.

Let's denote the mass of mercury as "x" and the mass of oxygen as "y". The mass percentage of mercury can be calculated using the following formula:

Mass Percentage of Mercury = (Mass of Mercury / Total Mass of Compound) * 100

Given that the mass percentage of mercury in the compound is 96.2%, we can set up the equation:

96.2 = (x / (x + y)) * 100

We also know that the relative molecular mass of the compound is 416. Using this information, we can set up another equation:

Relative Molecular Mass = Mass of Mercury + Mass of Oxygen

416 = x + y

By solving these two equations simultaneously, we can determine the values of x and y, which will allow us to determine the formula of the compound.

Let's calculate the values of x and y.