Question

составьте молекулярные и сокращенные ионные уравнения реакций между соляной кислотой и нитратом свинца 2​

Answer 1

Ответ:

Pb(NO3)2 + 2HCl (разб.)→ PbCl2↓ + 2HNO3

Pb²⁺ + 2NO3⁻ + 2H⁺ 2Cl⁻ → PbCl2↓ + 2H⁺ + 2NO3⁻

Pb²⁺ + 2Cl⁻ → PbCl2↓

Объяснение:

Answer 2

Molecular Equation:

The molecular equation for the reaction between hydrochloric acid (HCl) and lead nitrate (Pb(NO3)2) is as follows: Pb(NO3)2 + 2HCl → PbCl2 + 2HNO3.

Ionic Equation:

The ionic equation for the reaction between hydrochloric acid (HCl) and lead nitrate (Pb(NO3)2) is as follows: Pb^2+ + 2NO3^- + 2H^+ + 2Cl^- → PbCl2 + 2H^+ + 2NO3^-.

Summary:

When hydrochloric acid reacts with lead nitrate, it forms lead chloride and nitric acid. The molecular equation is Pb(NO3)2 + 2HCl → PbCl2 + 2HNO3, and the ionic equation is Pb^2+ + 2NO3^- + 2H^+ + 2Cl^- → PbCl2 + 2H^+ + 2NO3^-.