Question

Концентрированная серная кислота является окислителем в химических реакциях Cu+H2SO4= CuSO4+ H2O+SO2

Answer 1

Ответ: 1, 4. Cu + 2H2SO4(конц.) ⟶ CuSO4 + SO2↑ + 2H2O S+6 + 2ē ⟶ S+4 1 окислитель (восстановление) Cu0 - 2ē ⟶ Cu+2 1 восстановитель (окисление) C + 2H2SO4 ⟶ CO2 + 2SO2 + 2H2O S+6 + 2ē ⟶ S+4 2 окислитель (восстановление) C0 - 4ē ⟶ C+4 1 восстановитель (окисление) Вроде так!

Answer 2

Chemical Reaction Involving Concentrated Sulfuric Acid

Concentrated sulfuric acid (H2SO4) can act as an oxidizing agent in chemical reactions. When reacting with certain substances, it can undergo redox reactions, where it itself gets reduced and the other substance gets oxidized. An example of a chemical reaction involving concentrated sulfuric acid is the reaction with copper (Cu).

The chemical equation for the reaction between copper and concentrated sulfuric acid is as follows: Cu + H2SO4 → CuSO4 + SO2 + H2O.

This reaction results in the formation of copper sulfate (CuSO4), sulfur dioxide (SO2), and water (H2O) as products. The sulfuric acid acts as an oxidizing agent in this reaction, causing the copper to undergo oxidation.

This information is supported by the following search snippets: - Source "Cu + H2SO4 → CuSO4 + SO2 + H2O." - Source "H2SO4, KMnO4 - oxidizing agents."

Therefore, concentrated sulfuric acid can indeed act as an oxidizing agent in chemical reactions, as demonstrated in the reaction with copper.