Question

Какая масса Ca(OH2) образуется при взаимодействии 25 грамм CaO с H2O ​

Answer 1

Ответ прикреплён в виде фотографии:

Answer 2

Ответ:

33,3

Объяснение:

Answer 3

Calculation of the Mass of Ca(OH)2 Formed

When 25 grams of CaO reacts with H2O, it forms Ca(OH)2. The balanced chemical equation for this reaction is:

CaO + H2O → Ca(OH)2

To calculate the mass of Ca(OH)2 formed, we can use the stoichiometry of the reaction. From the balanced equation, we can see that 1 mole of CaO reacts with 1 mole of H2O to produce 1 mole of Ca(OH)2.

The molar mass of CaO is approximately 56.08 g/mol, and the molar mass of Ca(OH)2 is approximately 74.09 g/mol.

Using this information, we can calculate the mass of Ca(OH)2 formed as follows:

1. Calculate the moles of CaO: - Moles of CaO = Mass of CaO / Molar mass of CaO - Moles of CaO = 25 g / 56.08 g/mol

2. Since the reaction is 1:1 between CaO and Ca(OH)2, the moles of CaO will be equal to the moles of Ca(OH)2 formed.

3. Calculate the mass of Ca(OH)2: - Mass of Ca(OH)2 = Moles of Ca(OH)2 * Molar mass of Ca(OH)2

Let's calculate the mass of Ca(OH)2 formed using the given information.

Calculation: 1. Moles of CaO = 25 g / 56.08 g/mol = 0.446 moles 2. Moles of Ca(OH)2 = 0.446 moles 3. Mass of Ca(OH)2 = 0.446 moles * 74.09 g/mol = 33.05 grams

Therefore, the mass of Ca(OH)2 formed when 25 grams of CaO reacts with H2O is approximately 33.05 grams.