Question

Масса метаналя, образующегося при окислении 10 г метилового спирта

Answer 1

Ответ:

9,375 грамм

Объяснение:

По реакция окисления оксидом меди, каталитическим окислением

m(CHOH)=(10/32)*30=9,375

Answer 2

Calculating the Mass of Formaldehyde Formed

When 10 grams of methyl alcohol (methanol) undergoes oxidation, it forms formaldehyde. To calculate the mass of formaldehyde formed, we can use the chemical equation for the oxidation of methanol to formaldehyde.

The balanced chemical equation for the oxidation of methanol to formaldehyde is: CH3OH + [O] → CH2O + H2O

Where: - CH3OH represents methanol - [O] represents the oxidizing agent - CH2O represents formaldehyde - H2O represents water

To calculate the mass of formaldehyde formed, we need to consider the stoichiometry of the reaction and the molar masses of the substances involved.

Stoichiometry and Molar Masses

The molar mass of methanol (CH3OH) is approximately 32.04 g/mol. The molar mass of formaldehyde (CH2O) is approximately 30.03 g/mol.

From the balanced chemical equation, we can see that 1 mole of methanol (CH3OH) reacts to produce 1 mole of formaldehyde (CH2O).

Calculation

Using the molar masses and stoichiometry, we can calculate the mass of formaldehyde formed when 10 grams of methanol undergoes oxidation.

1. Calculate the number of moles of methanol: - Number of moles = Mass / Molar mass - Number of moles = 10 g / 32.04 g/mol - Number of moles ≈ 0.312 moles

2. Since the stoichiometry of the reaction is 1:1, the number of moles of formaldehyde formed is also approximately 0.312 moles.

3. Calculate the mass of formaldehyde formed: - Mass of formaldehyde = Number of moles × Molar mass - Mass of formaldehyde ≈ 0.312 moles × 30.03 g/mol - Mass of formaldehyde ≈ 9.36 grams

Conclusion

When 10 grams of methyl alcohol undergoes oxidation, approximately 9.36 grams of formaldehyde are formed.

This calculation is based on the stoichiometry of the chemical reaction and the molar masses of methanol and formaldehyde.