Question

1) Сколько вещества содержится в 105 г BaCl2?​

Answer 1

Ответ:

0,5042 моль

Объяснение:

n(BaCl2)=105/208.233=0,5042 моль

Answer 2

Amount of Substance in 105g of BaCl2

The amount of substance in 105g of BaCl2 can be calculated using the molar mass of BaCl2 and Avogadro's number.

The molar mass of BaCl2 can be calculated by adding the atomic masses of barium (Ba) and chlorine (Cl) together. According to source the molar mass of BaCl2 is 208.23 g/mol.

Using Avogadro's number, which is approximately 6.02 x 10^23, we can calculate the amount of substance in 105g of BaCl2.

Calculation: - Molar mass of BaCl2 = 208.23 g/mol - Amount of substance = Mass / Molar mass - Amount of substance = 105g / 208.23 g/mol - Amount of substance ≈ 0.504 mol

Therefore, there are approximately 0.504 moles of BaCl2 in 105g of the substance