Question

Нiтратну кислоту в помисловостi отримують з нiтроген (IV) оксиду. NO2 + H2O + O2 = HNO3 Обчислить вихiд нiтртноi кислоти, якщо, викорисавши нiтроген (IV) оксид кiлькостi речовини 250 моль, одержали 11,025 кг кислоти

Answer 1

Ответ:

70%

Объяснение:

Исходя из сводной формулы

4NO2+2H2O+O2-> 4HNO3

n(HNO3)=n(NO2)

m(HNO3)=250*63.012=15.753 кг

W=11.025/15.753=0,6998*100=69.98% (70%)

Answer 2

According to the given chemical equation, the reaction between nitrogen (IV) oxide (NO2), water (H2O), and oxygen (O2) produces nitric acid (HNO3). The question asks to calculate the yield of nitric acid when 250 moles of nitrogen (IV) oxide are used to obtain 11.025 kg of acid.

To calculate the yield of nitric acid, we need to determine the molar mass of nitric acid (HNO3). The molar mass of hydrogen (H) is approximately 1 g/mol, nitrogen (N) is approximately 14 g/mol, and oxygen (O) is approximately 16 g/mol. Adding these values together, we find that the molar mass of nitric acid is approximately 63 g/mol.

Next, we need to convert the given mass of nitric acid (11.025 kg) to moles. Since 1 kg is equal to 1000 grams, we can multiply the given mass by 1000 to convert it to grams. Then, we can divide the mass in grams by the molar mass of nitric acid to obtain the number of moles.

Let's calculate the number of moles of nitric acid:

11.025 kg * 1000 g/kg = 11025 g 11025 g / 63 g/mol ≈ 175 moles

Therefore, the yield of nitric acid is approximately 175 moles when 250 moles of nitrogen (IV) oxide are used.

Please note that the calculation assumes the reaction goes to completion and there are no other limiting factors or side reactions involved.

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