Question

Cu растворили в 90% растворе .H2SO4 массой 196 гр.,выделенный газ пропустили ,через избыток щелочи калия,найти массу полученной соли,если выход продукта реакции 80%​

Answer 1

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Answer 2

Calculation of the Mass of the Obtained Salt

To calculate the mass of the obtained salt, we need to consider the reaction between the sulfuric acid (H2SO4) and potassium hydroxide (KOH). The balanced equation for this reaction is as follows:

H2SO4 + 2KOH -> K2SO4 + 2H2O

From the given information, we know that 196 grams of sulfuric acid (H2SO4) were dissolved in a 90% solution. However, we need to determine the mass of the obtained salt when the product yield is 80%.

To calculate the mass of the obtained salt, we can follow these steps:

1. Calculate the moles of sulfuric acid (H2SO4) used: - The molar mass of H2SO4 is 98.09 g/mol. - Divide the mass of H2SO4 (196 g) by its molar mass to get the number of moles.

2. Use the stoichiometry of the balanced equation to determine the moles of the obtained salt (K2SO4): - According to the balanced equation, 1 mole of H2SO4 reacts to produce 1 mole of K2SO4. - Multiply the moles of H2SO4 by the stoichiometric coefficient of K2SO4 (1) to get the moles of K2SO4.

3. Calculate the mass of the obtained salt (K2SO4): - Multiply the moles of K2SO4 by its molar mass (174.26 g/mol) to get the mass of K2SO4.

However, we need to take into account that the product yield is 80%. This means that only 80% of the calculated mass of K2SO4 will be obtained.

Let's perform the calculations:

1. Moles of H2SO4 used: - Molar mass of H2SO4: 98.09 g/mol - Moles of H2SO4 = Mass of H2SO4 / Molar mass of H2SO4 - Moles of H2SO4 = 196 g / 98.09 g/mol

2. Moles of K2SO4 obtained: - According to the balanced equation, the stoichiometric coefficient of K2SO4 is 1. - Moles of K2SO4 = Moles of H2SO4

3. Mass of K2SO4 obtained: - Molar mass of K2SO4: 174.26 g/mol - Mass of K2SO4 = Moles of K2SO4 * Molar mass of K2SO4

4. Adjusted mass of K2SO4 obtained (considering 80% yield): - Adjusted mass of K2SO4 = Mass of K2SO4 * Yield percentage

Let's calculate the values:

1. Moles of H2SO4 used: - Moles of H2SO4 = 196 g / 98.09 g/mol = 2 moles

2. Moles of K2SO4 obtained: - Moles of K2SO4 = Moles of H2SO4 = 2 moles

3. Mass of K2SO4 obtained: - Mass of K2SO4 = Moles of K2SO4 * Molar mass of K2SO4 = 2 moles * 174.26 g/mol = 348.52 g

4. Adjusted mass of K2SO4 obtained (considering 80% yield): - Adjusted mass of K2SO4 = Mass of K2SO4 * Yield percentage = 348.52 g * 0.8 = 278.82 g

Therefore, the mass of the obtained salt (K2SO4) is approximately 278.82 grams when the product yield is 80%.