Question

Железо массой 448 г полностью прореагировало с хлором. Рассчитайте массу образовавшегося вещества FeCl3

Answer 1

Объяснение:

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Answer 2

Answer in detail. Iron with a mass of 448 g completely reacted with chlorine. Calculate the mass of the resulting substance FeCl3

To answer this question, we need to use the concept of stoichiometry, which is the calculation of the quantities of reactants and products in a chemical reaction. We also need to know the balanced chemical equation for the reaction between iron and chlorine, which is:

$$2Fe + 3Cl_2 \rightarrow 2FeCl_3$$

This equation tells us that for every 2 moles of iron, we need 3 moles of chlorine gas to produce 2 moles of iron(III) chloride. To find the mass of the product, we need to follow these steps:

1. Convert the mass of iron to moles using its molar mass, which is 55.85 g/mol. 2. Use the mole ratio from the balanced equation to find the moles of iron(III) chloride produced. 3. Convert the moles of iron(III) chloride to mass using its molar mass, which is 162.2 g/mol.

Let's do the calculations:

1. $$\text{moles of iron} = \frac{\text{mass of iron}}{\text{molar mass of iron}} = \frac{448 \text{ g}}{55.85 \text{ g/mol}} = 8.02 \text{ mol}$$ 2. $$\text{moles of iron(III) chloride} = \text{moles of iron} \times \frac{\text{mole ratio of iron(III) chloride}}{\text{mole ratio of iron}} = 8.02 \text{ mol} \times \frac{2 \text{ mol}}{2 \text{ mol}} = 8.02 \text{ mol}$$ 3. $$\text{mass of iron(III) chloride} = \text{moles of iron(III) chloride} \times \text{molar mass of iron(III) chloride} = 8.02 \text{ mol} \times 162.2 \text{ g/mol} = 1300.4 \text{ g}$$

Therefore, the mass of the resulting substance FeCl3 is 1300.4 g. I hope this helps you understand the problem.

: [Iron - Wikipedia] : [Iron(III) chloride - Wikipedia]