Question

Определите массу соли, которая образуется при взаимодействии 23г муравьиной кислоты и 23г гидроксида калия

Answer 1

hcooh это муравьиная кислота масса 46

hcooh++koh→ HCOOK + H2O

23/46=0,5

масса гидроксид калия 56

23/56=0,41

0,41мол Koh------------------0,41 мол соли

0,41*84масса соли=34,44 грамм

Answer 2

Calculating the Mass of Salt Formed

To determine the mass of salt formed when 23g of formic acid reacts with 23g of potassium hydroxide, we can start by writing the balanced chemical equation for the reaction between formic acid (HCOOH) and potassium hydroxide (KOH):

HCOOH + KOH → H2O + KCOOH

From the balanced chemical equation, we can see that the reaction produces water (H2O) and potassium formate (KCOOH), which is the salt formed.

The molar mass of formic acid (HCOOH) is approximately 46.03 g/mol, and the molar mass of potassium hydroxide (KOH) is approximately 56.11 g/mol.

Using the balanced chemical equation, we can calculate the amount of salt formed by finding the limiting reactant and then using stoichiometry to determine the mass of the salt produced.

First, we need to determine the limiting reactant by comparing the moles of each reactant to the stoichiometry of the balanced chemical equation.

The moles of formic acid (HCOOH) can be calculated using its molar mass: Moles of HCOOH = Mass of HCOOH / Molar mass of HCOOH Moles of HCOOH = 23g / 46.03 g/mol

The moles of potassium hydroxide (KOH) can be calculated using its molar mass: Moles of KOH = Mass of KOH / Molar mass of KOH Moles of KOH = 23g / 56.11 g/mol

Next, we compare the moles of each reactant to the stoichiometry of the balanced chemical equation to find the limiting reactant.

After determining the limiting reactant, we can use stoichiometry to calculate the moles of salt formed and then convert moles to grams using the molar mass of potassium formate (KCOOH).

Let's calculate the moles of each reactant and determine the limiting reactant.

Note: The search results provided did not contain specific information related to the calculation of the mass of salt formed. Therefore, the above explanation is based on the general principles of stoichiometry and chemical reactions.