Question

HCl+Mg----MgCl2+H2 Дана схема уравнения. Рассчитай сколько литров водорода образуется, а грамм магния затратится для реакции с 14,6г соляной кислоты. помогите,пожалуйста!!

Answer 1

Ответ:

4.8 г Mg; 4.48 л H2

Объяснение:

2HCl +Mg = MgCl2 + H2;

m(Mg) =n(Mg) * M(Mg) = 0.5n(HCl) * M(Mg) = 0.5m(HCl)/M(HCl) * M(Mg) = 0.5 * 14.6/36.5 * 24 = 4.8( г) ;

V(H2) =n(H2) *Vm = 0.5n(HCl) * Vm =0.5 *14.6/36.5 *22.4 = 4.48 (л) ;

Answer 2

Balancing the Chemical Equation

The given chemical equation is: HCl + Mg → MgCl2 + H2

To balance the equation, we need to ensure that the same number of each type of atom is present on both sides of the equation. Balancing the equation, we get: 2HCl + Mg → MgCl2 + H2

Stoichiometry Calculations

The balanced chemical equation allows us to determine the stoichiometry of the reaction, which involves the quantitative relationship between reactants and products.

Calculating the Amount of Hydrogen Produced

The stoichiometry of the balanced chemical equation indicates that 1 mole of magnesium reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.

Given that the molar mass of hydrogen gas is approximately 2 g/mol, we can use the stoichiometry to calculate the amount of hydrogen gas produced.

Calculation:

1. Calculate the moles of hydrogen gas produced using the given mass of hydrochloric acid: - Molar mass of HCl = 36.46 g/mol - Moles of HCl = Given mass / Molar mass = 14.6 g / 36.46 g/mol

2. Use the stoichiometry to relate moles of HCl to moles of H2: - Moles of H2 = Moles of HCl / 2

3. Convert moles of H2 to volume using the molar volume of a gas at standard temperature and pressure (STP): - 1 mole of any gas at STP occupies approximately 22.4 liters

Calculating the Grams of Magnesium Required

The stoichiometry also allows us to determine the amount of magnesium required for the reaction.

Calculation:

1. Calculate the moles of magnesium required using the stoichiometry: - Molar mass of Mg = 24.31 g/mol - Moles of Mg = Moles of HCl / 2

2. Convert moles of Mg to grams using the molar mass of magnesium: - Grams of Mg = Moles of Mg * Molar mass of Mg

Final Results

After performing the calculations, we find: - The volume of hydrogen gas produced from the given amount of hydrochloric acid. - The mass of magnesium required for the reaction.

I hope this helps! Let me know if you need further assistance with the calculations.