Question

Складіть рiвняння реакцiй відновленням таких оксидiв: алюміній оксиду, ферум(III) оксиду, плюмбум(I) оксиду. Укажіть окисник і відновник.

Answer 1

Ответ Смотри ниже
Ответ:
Окис-ль - ОКИСЛИТЕЛЬ
В-ль - ВОСТАНОВИТЕЛЬ

Answer 2

Equation for the Reduction Reactions of Aluminum Oxide, Iron(III) Oxide, and Lead(II) Oxide

The reduction reactions for the following oxides can be represented by the following equations:

1. Aluminum Oxide (Aluminum(III) Oxide): - Equation: 2Al2O3 + 3C → 4Al + 3CO2 - Oxidant: Aluminum Oxide (Al2O3) - Reductant: Carbon (C)

2. Iron(III) Oxide: - Equation: 2Fe2O3 + 3C → 4Fe + 3CO2 - Oxidant: Iron(III) Oxide (Fe2O3) - Reductant: Carbon (C)

3. Lead(II) Oxide: - Equation: 2PbO + C → 2Pb + CO2 - Oxidant: Lead(II) Oxide (PbO) - Reductant: Carbon (C)

Please note that these equations represent the reduction reactions of the respective oxides. The oxidant is the substance being reduced (gaining electrons), while the reductant is the substance being oxidized (losing electrons) in the reaction.