Question

Обчисли масову частку Оксигену в складі калій перманганту​

Answer 1

Ответ:

41.3%

Объяснение:

w(O) = N(O) * Ar(O)/Mr(KMnO4) * 100% = 4 *16/155 * 100 = 41.3(%)

Answer 2

Calculating the Molar Mass of Potassium Permanganate

To calculate the molar mass of potassium permanganate (KMnO4), we need to consider the atomic masses of each element in the compound and then sum them up.

- The molar mass of potassium (K) is approximately 39.10 g/mol. - The molar mass of manganese (Mn) is approximately 54.94 g/mol. - The molar mass of oxygen (O) is approximately 16.00 g/mol.

Now, let's calculate the molar mass of potassium permanganate:

Molar mass of KMnO4 = (1 * molar mass of K) + (1 * molar mass of Mn) + (4 * molar mass of O)

Molar mass of KMnO4 = (1 * 39.10 g/mol) + (1 * 54.94 g/mol) + (4 * 16.00 g/mol)

Molar mass of KMnO4 = 39.10 g/mol + 54.94 g/mol + 64.00 g/mol

Molar mass of KMnO4 = 158.04 g/mol

Calculating the Mass Percentage of Oxygen in Potassium Permanganate

To calculate the mass percentage of oxygen in potassium permanganate, we can use the following formula:

Mass percentage of oxygen = (Mass of oxygen / Molar mass of KMnO4) * 100%

Given that there are 4 oxygen atoms in KMnO4, we can calculate the mass percentage of oxygen:

Mass percentage of oxygen = (4 * molar mass of O / molar mass of KMnO4) * 100%

Mass percentage of oxygen = (4 * 16.00 g/mol / 158.04 g/mol) * 100%

Mass percentage of oxygen = (64.00 g/mol / 158.04 g/mol) * 100%

Mass percentage of oxygen ≈ 40.5%

So, the mass percentage of oxygen in potassium permanganate is approximately 40.5%.